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Calculating chemical treatments for aquaculture production - Responsible Seafood Advocate

Calculating chemical treatments for aquaculture production

Claude E. Boyd, Ph.D.

Calculations for large and small bodies of water

chemical treatments
Liming materials are typically applied on the basis of their neutralizing value. They can be broadcast from a boat or the pond edge.

Managers often must treat aquaculture ponds with fertilizers, liming materials, osmoregulatory enhancers, coagulants, oxidants or algicides. Dosages of these materials should be calculated accurately to avoid waste, assure efficacy and prevent possible damage to the culture species or culture environment. Various chemical treatments also may be applied to other types of holding and grow-out units.

Pond treatments usually are made on the basis of pond area or chemical concentration desired. The areas and average depths of ponds are typically determined during construction. However, while pond areas are usually remembered, average depths often are forgotten. Moreover, the depths of ponds change over time in response to sediment accumulation and fluctuate according to practices for replacing seepage and evaporation.

Pond volume, depth

Standard surveying techniques can accurately estimate the volume of a pond. However, it is far simpler – and sufficiently accurate – to obtain pond depth by averaging soundings made at many places in a pond (Fig. 1). Soundings should be taken when the pond water level is equal to the elevation of the overflow structure intake.

depths of ponds
Fig. 1: Two simple methods for taking soundings to estimate average depths of ponds.

Ponds usually are constructed so that a 15- to 30-cm decline in surface water elevation does not appreciably decrease surface area. At times when the pond is not full, the average depth can be estimated as the full depth minus the vertical distance from the intake of the overflow structure to the water surface. Volume is calculated as average depth multiplied by surface area.

Treatment products

Some products used for pond treatments are solid, particulate materials, such as agricultural limestone, lime, traditional fertilizers, copper sulfate crystals and potassium permanganate. Others are liquids, some examples of which are fluid fertilizers, chelated copper solutions, formalin, calcium hypochlorite solutions and molasses.

Pond treatment products seldom contain 100 percent of the active ingredient. Liming materials are applied on the basis of their neutralizing value or percentage calcium carbonate equivalence – the neutralizing value of different liming products can range from less than 75 percent to more than 150 percent. The active ingredients of fertilizers are their nutrients, especially nitrogen and phosphorus.

Although many farmers still apply fertilizers on a quantity-per-hectare basis, a growing trend is to apply a specific quantity of nutrients per hectare or dose of fertilizer calculated to increase the concentration of nutrients in the pond water by a specific amount. Copper sulfate can be applied to provide a certain concentration of copper, and copper sulfate contains only 25 percent of the active ingredient copper. Crushed rock salt (sodium chloride) is applied to ponds to raise the chloride concentration to a specific level to combat nitrite toxicity. This product is seldom less than 97 percent pure, and pure sodium chloride is nearly 61 percent chloride. Thus, the active ingredient content of the salt applied to ponds is about 58 to 59 percent.

The specific gravity of liquid products used in aquaculture often differs from the specific gravity of water, which has a specific gravity of 1. Fluid fertilizer preparations usually have a specific gravity around 1.4, meaning they are 1.4 times denser than water. A product with a specific gravity of 1.0 and 50 percent active ingredient would contain 0.5 kg active ingredient per liter, but a product with specific gravity of 1.4 and the same percentage of the active ingredient would contain 0.7 kg per liter.

Calculations for large ponds

In calculating the amounts of substances to apply to ponds, one must adjust for the percentage of the active ingredients in solid products. Adjustments for both active ingredient content and specific gravity must be made for liquid products. Equations are provided in Table 1 for use in estimating pond treatment rates. An example is shown below.

Boyd, Equations for calculating chemical treatment, Table 1

Chemical FormTreatment TypeEquation Metric*Equation English**
1. SolidWeight/areaA x R
A.I./100
A x R
A.I./100
2. SolidWeight/volume(A x D x C) x 10
A.I./100
(A x D x C) x 2.71
(A.I./100)
3. LiquidVolume/volume(A x D x C) x 10
(A.I./100) x S.G.
(A x D x C) x 2.71
(A.I./100) x S.G.
Table 1. Equations for calculating chemical treatment.
*A = area (ha), D = average depth (m), R = treatment rate for active ingredient (kg/ha), C = treatment concentration of active ingredient (g/m3 or mg/l),
A.I. = percentage active ingredient, S.G. = specific gravity (lb/gal),
10 = factor for converting g/m3 to kg/ha-m.
** A = area (acres), D = average depth (ft), R = treatment rate for active
ingredient (lb/acre), C = treatment concentration of active ingredient
(ppm or g/m3), A.I. = percentage active ingredient, S.G. = specific gravity (lb/gal),
2.71 = factor for converting ppm to lb/acre-ft.

Example: What is the amount of triple superphosphate fertilizer (46 percent phosphorus pentoxide, 20 percent phosphorus) needed to provide a treatment rate of 3 kg phosphorus/ha in a 5-hectare pond? Use the metric Equation 1 from Table 1.

Liming materials can be applied to bottoms of empty ponds or to the surfaces of full ponds. In either case, the liming material should be spread uniformly over the entire pond area. Other pond treatments usually are made to ponds filled with water. Fertilizers and other products should be dissolved and mixed uniformly in the water for best results. Most granular materials settle to the pond bottom before completely dissolving if broadcast over pond surfaces.

Liquids that are denser than water settle to the bottom without completely dissolving in the water column if splashed directly over the pond surface. Fertilizers, other granular materials and liquids should be dissolved or made into a slurry in a container of pond water before applying.

The resulting solution or slurry can be splashed over the surface, released into the turbulence caused by the motor while a boat is driven in a zigzag pattern over the pond or sprayed over the pond surface from the edges or a boat. The operation of mechanical aerators in ponds following applications of pond treatments encourages mixing of the product throughout the water volume.

Calculations for small ponds

Equations are provided in Table 2 for the calculation of the amounts of substances necessary for treating small ponds or other fish production units. The basic equations for calculating volumes of regular-shaped vessels for fish culture follow: square, V = L2 D; rectangular, V = L x W x D; circular, V = pi x rx D, where V = volume (m3 or ft3), L = length (m or ft), W = width (m or ft), D = water depth (m or ft) and r = radius or one-half of diameter (m or ft). An example is provided.

Boyd, Equations for calculating chemical treatment amounts, Table 2

Chemical FormTreatment TypeEquation Metric*Equation English**
1. SolidWeight/areaA x R
A.I./100
A x R
A.I./100
2. SolidWeight/volumeV x C
A.I./100
(V x C) x 0.001
(A.I./100) x S.G.
Table 2. Equations for calculating chemical treatment amounts for small holding or culture units.
* A = area (m2), R = treatment rate for active ingredient (g/m2),
C = treatment concentration for active ingredient (g/m3 or mg/l),
A.I. = percentage active ingredient, S.G. = specific gravity (oz/fluid oz).
** A = area (ft2), R = treatment rate for active ingredient (lb/ft2),
C = treatment concentration of active ingredient (ppm or g/m3),
A.I. = percentage active ingredient, S.G. = specific gravity (oz/fluid oz),
0.001 = factor for converting ppm to oz/ft3.

Example: What is the amount of liquid fertilizer (15 percent phosphorus, specific gravity 1.38) needed to provide a treatment rate of 0.5 mg phosphorus per liter in a 400-cubic-meter pond? Use the metric equation 3 from Table 2.

(Editor’s Note: This article was originally published in the May/June 2009 print edition of the Global Aquaculture Advocate.)

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